fervo / enum-bundle
A library to integrate enums into the Symfony framework
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Type:symfony-bundle
Requires
- php: ^7.0|^8.0
- doctrine/common: ^3.0
- doctrine/doctrine-bundle: ^2.0
- doctrine/persistence: ^2.0|^3.0
- myclabs/php-enum: ^1.3
- symfony/form: ^3.0|^4.0|^5.0
- symfony/framework-bundle: ^3.0|^4.0|^5.0
- symfony/translation: ^3.0|^4.0|^5.0
Suggests
- jms/serializer-bundle: If you want to serialize data using JMS Serializer
- sensio/framework-extra-bundle: If you wan to use ParamConverter
- twig/twig: If you want to use enum in your Twig templates
README
Provides a MyCLabs\Enum integration with Doctrine for your Symfony projects.
Installation
Step 1: Download the Bundle
$ composer require fervo/enum-bundle "^2.0"
Step 2: Enable the Bundle
<?php
// app/AppKernel.php
// ...
class AppKernel extends Kernel
{
public function registerBundles()
{
$bundles = array(
// ...
new Fervo\EnumBundle\FervoEnumBundle(),
);
// ...
}
// ...
}
Step 3: Configure your enum
fervo_enum:
fqcn_choice_label_prefix: true # For Backward compatibily, should be explicitely set to true
enums:
AppBundle\Enum\Gender:
doctrine_type: gender # Type name used in doctrine annotations
form_type: gender # Used in translation keys
Step 4: Create your enum
<?php
namespace AppBundle\Enum\Gender;
use MyCLabs\Enum\Enum;
class Gender extends Enum
{
const MALE = 'male';
const FEMALE = 'female';
}
Step 5: Use the enum in a doctrine entity
<?php
namespace AppBundle\Entity;
use AppBundle\Enum\Gender;
use Doctrine\ORM\Mapping as ORM;
/**
* @ORM\Entity()
*/
class Person
{
// ...
/**
* @ORM\Column(type="gender")
*/
protected $gender;
// ...
public function getGender()
{
return $this->gender;
}
public function setGender(Gender $gender)
{
$this->gender = $gender;
}
// ...
}
Step 6: Use the enum in Symfony forms
The bundle auto-generates a corresponding form type for each configured enum. The FQCN for the form type is on the format FervoEnumBundle\Generated\Form\{{enum class name}}Type
. So with the enum class in the example above, it could be used in a form type in the following way.
<?php
namespace AppBundle\Form\Type;
use FervoEnumBundle\Generated\Form\GenderType;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
class EmployeeType extends AbstractType
{
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
// ...
->add('gender', GenderType::class)
// ...
;
}
}
If the underlying object of the form type is a doctrine mapped entity, the type can also be guessed by the framework. But it is a good practice to always specify the FQCN in form types.
Or you can use EnumType
with configured options:
<?php
namespace AppBundle\Form\Type;
use AppBundle\Enum\Gender;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
class EmployeeType extends AbstractType
{
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
// ...
->add('gender', EnumType::class, [
'class' => Gender::class,
'choice_label_prefix' => 'gender', // optional
])
// ...
;
}
}
Step 7: Specify translations for the enum values
The form type looks by default for the translation of the enum values in the enums
translation domain. The translation keys are on the format {{configured form_type name}}.{{enum constant value}}
. So going with the example the translation keys would be gender.male
and gender.female
.
Additional functionality
Use the enum with Symfony @ParamConverter
<?php
namespace AppBundle\Controller;
use AppBundle\Enum\Gender;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\ParamConverter;
use Symfony\Bundle\FrameworkBundle\Controller\Controller;
class EmployeeController extends Controller
{
/**
* @ParamConverter("gender")
*/
public function indexAction(Gender $gender)
{
// ...
}
}
Use the enum with JMS\Serializer
<?php
namespace AppBundle\Entity;
use AppBundle\Enum\Gender;
use JMS\Serializer\Annotation as JMS;
class Person
{
// ...
/**
* @JMS\Type("gender")
*/
protected $gender;
// ...
public function getGender()
{
return $this->gender;
}
public function setGender(Gender $gender)
{
$this->gender = $gender;
}
// ...
}