gbuckingham89/youtube-rss-parser

This package is abandoned and no longer maintained. No replacement package was suggested.

A simple parser for reading a YouTube RSS feed.

0.4.0 2021-03-12 11:05 UTC

Requires

• php: ^7.1.8|^8.0
• guzzlehttp/guzzle: ^6.2|^7.2
• nesbot/carbon: ^2.0

MIT

• George Buckingham

• parser
• youtube
• rss

README

A simple PHP parser for reading a YouTube RSS feed. It provides a object oriented interface for accessing the RSS feed data. Perfect for when you need to access recent videos, but don't want to use the full YouTube API.

Requirements

Requires PHP 7.1.8 or greater. Uses guzzlehttp/guzzle as a HTTP client and nesbot/carbon for handling dates. See composer.json for more details.

If you require support for an older PHP version (>=5.5), see release v0.1.0.

Installation

Use Composer:

composer require gbuckingham89/youtube-rss-parser

Usage

To get started you'll need to create an instance of the parser;

$parser = new \Gbuckingham89\YouTubeRSSParser\Parser();

You can then load the RSS feed from a URL:

$rss_url = 'https://www.youtube.com/feeds/videos.xml?channel_id=CHANNEL_ID_HERE';
$parser->loadUrl($rss_url);

Or, if you're in a hurry, you can also pass in the URL as the first argument when you instantiate the parser object.

Or if you've already got the XML of RSS feed content as a string, you can load it via that:

$rss_content = 'RSS FEED CONTENT';
$parser->loadString($rss_content);

Both of these methods then return an instance of \Gbuckingham89\YouTubeRSSParser\Channel. You can also access the channel property or call the channel method on the Parser instance to get the Channel object.

You can then access the properties of the channel (see the class file). The videos property is an array of \Gbuckingham89\YouTubeRSSParser\Video objects, on which you can access the properties of the video (see the class file).

Prefer working with arrays? Or JSON? You can simply call the toArray or toJson on both the Channel and Videos objects.

Contributing / bugs

Just open an issue / pull request if you find a bug, or want to contribute!

Copyright and license

Code and documentation copyright 2017 George Buckingham. Code released under the MIT License.