This package is abandoned and no longer maintained. The author suggests using the php-extended/php-inspector-object package instead.

A library to tell what is that variable, safely

2.0.1 2020-02-16 10:20 UTC

This package is auto-updated.

Last update: 2020-08-17 19:16:03 UTC


A library to tell what is that variable, safely.


The installation of this library is made via composer. Download composer.phar from their website. Then add to your composer.json :

	"require": {
		"php-extended/php-inspect": "^2",

Then run php composer.phar update to install this library. The autoloading of all classes of this library is made through composer's autoloader.

Basic Usage

In your code (for example, when trying to use a variable in an exception):

use PhpExtended\Inspect\Inspector;

if(!'<condition not satisfied with $myVar >')
	throw new Exception(strtr(
		'The given variable "myVar" is not an object, it\'s a {thing}.',
		['{thing}' => Inspector::inspect($myVar)]

The expected results are the following :

use PhpExtended\Inspect\Inspector;

echo Inspector::inspect(null); 					// echo 'null'
echo Inspector::inspect(false); 				// echo 'boolean'
echo Inspector::inspect('myvar');				// echo 'string'
echo Inspector::inspect(1);						// echo 'integer'
echo Inspector::inspect(1.5);					// echo 'float'
echo Inspector::inspect(new stdClass()); 		// echo 'object(stdClass)'
echo Inspector::inspect(fopen(__FILE__, 'r'));	// echo 'resource(stream)'
echo Inspector::inspect([1]); 					// echo 'array(integer)'
echo Inspector::inspect([1.5]);					// echo 'array(float)'
echo Inspector::inspect([1, 1.5]);				// echo 'array(integer,float)'
echo Inspector::inspect([1, 2, 3]);			// echo 'array(integer)'
echo Inspector::inspect([new stdClass()]);	// echo 'array(object(stdClass))'
echo Inspector::inspect([[1]]);					// echo 'array(array(integer))'


MIT (See license file).