grummfy/laravel-route-controller

Define Router::controller() without breaking everything

1.0.0 2018-02-06 10:15 UTC

This package is auto-updated.

Last update: 2024-11-28 19:11:38 UTC


README

This library like other existing, give a way to deal with Router::controller. The key features:

  • allow caching of route
  • doesn't require extra manipulation
  • allow inheritance of route group
  • namespace independent

Compatible with laravel 5.5. (probably compatible with older version too).

Install

Install the dependencies

composer require grummfy/laravel-route-controller

Publish the configuration

php artisan vendor:publish --tag=config --provider=Grummfy\LaravelRouteController\RouteControllerProvider

Usage

Once the package is install and autodiscover (or you have added the provider manually), the package is ready to use.

In your route file, just do this:

Route::controller('/foo', \App\Http\Controllers\FooController::class);

It will take all the public method from the class (including traits) and convert it to route.

There is a third argument that you can use to add extra option, like a middleware or anything else.

Route::controller('/foo', \App\Http\Controllers\FooController::class, ['middleware' => 'can:baz']);

You got also an extra option, to don't allow heritance of methods from parent:

Route::controller('/foo', \App\Http\Controllers\FooController::class, ['middleware' => 'can:baz', 'heritage' => false]);

Example

Imagine that we have the class FooController (see example), in this case we will have a series of method that will be converted to routes:

  • index() -> /foo, foo.index
  • getStatus(string $status) -> /foo/status/{status}, foo.status.post
  • postStatus(string $status) -> /foo/status/{status}, foo.status.get
  • foo() -> /foo/foo, foo.foo
  • my() -> /foo/my, foo.my

TODO

  • unit test
  • QA tools
    • travis
    • styleci
    • scrutinizer
    • ...

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